From the ΔACD, | ||
tan 60° | = | |
= | ||
DC | = | AC ----- (i) |
From the ΔBCD, | ||
tan 75° | = | |
2 + | = | |
DC | = | BC(2 + ) ------ (ii) |
From eq (i) & (ii), we get | ||
AC | = | BC(2 + ) |
(AB + BC) | = | BC(2 + ) |
(30 + BC) | = | BC(2 + ) (∵ AB = 30) |
30 | = | BC(2 + – ) |
BC | = | 15 |
From eq(ii), DC | = | 15(2 + ) |